Given that the solutions of equation 2aX + 1 = - 3 and equation 5x = 10 are the same, find a

Given that the solutions of equation 2aX + 1 = - 3 and equation 5x = 10 are the same, find a

5x=10
x=2
Substituting 2aX + 1 = - 3
We get 4A = - 4
a=-1