Given that the equation 2aX + 9 = 5x + 6B has two different solutions, find the value of (B-A) ^ 2003

Given that the equation 2aX + 9 = 5x + 6B has two different solutions, find the value of (B-A) ^ 2003

2aX + 9 = 5x + 6b is a linear equation with one variable
The solution of linear equation of one variable is unique solution, no solution, or infinite solution
The condition is that the equation has two different solutions, corresponding to infinitely many solutions. At this time, we should ensure that the coefficients of each item on both sides of the equation are equal
There are 2A = 5 and 6B = 9
Then, a = 5 / 2, B = 3 / 2
(b-a)^2003
=(-1)^2003
= -1