Given the absolute value of x-3 + (y + 2 / 5) to the power of 2 = 0, find the value of X of Y

∵|x-3|≥0,(y+5/2)^2≥0
∴x-3=0,y+5/2=0
x=3,y=-5/2
y^x=(-5/2)^2=25/4

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