If it is known that the function f (x) defined on R is an odd function with period 2, then the equation f (x) has at least two properties in the interval [- 2,2]_____ A real number root If f (0) = 0, f (- 1) = - f (1) is obtained by odd function, and if f (2) = f (- 2) = f (0), f (1) = f (- 1) is obtained by period 2, then f (2) = f (- 2) = f (1) = f (- 1) = f (0) = 0, that is, there are at least five real roots I don't understand the answer“ So f (2) = f (- 2) = f (1) = f (- 1) = f (0) = 0 How can f (- 2) be equal to F (1) and f(-1) Where else do you get five real roots?

If it is known that the function f (x) defined on R is an odd function with period 2, then the equation f (x) has at least two properties in the interval [- 2,2]_____ A real number root If f (0) = 0, f (- 1) = - f (1) is obtained by odd function, and if f (2) = f (- 2) = f (0), f (1) = f (- 1) is obtained by period 2, then f (2) = f (- 2) = f (1) = f (- 1) = f (0) = 0, that is, there are at least five real roots I don't understand the answer“ So f (2) = f (- 2) = f (1) = f (- 1) = f (0) = 0 How can f (- 2) be equal to F (1) and f(-1) Where else do you get five real roots?

Answer: F (x) is a function with period 2, then: F (x) = f (x + 2) so: F (- 2) = f (- 2 + 2) = f (0) f (0) = f (0 + 2) = f (2) so: f (- 2) = f (0) = f (2) = 0f (x) is an odd function, f (0) = 0f (- x) = - f (x) so: F (- 1) = - f (1) f (- 1) = f (- 1 + 2) = f (1) from the solution of the above two formulas: F (- 1) = f (1) = 0 so: F (