It is known that P and Q are positive integers, and the two roots of the equation 7X2 PX + 2009q = 0 are prime numbers, then p + Q=______ .
If X1 + x2 = p7x1x2 = 2009q7 = 287q = 7 × 41 × qx1 and X2 are prime numbers, then only X1 and X2 are 7 and 41, and q = 1, so 7 + 41 = p7p = 336, so p + q = 337
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