The solution set of absolute value inequality / 2x + 1 / greater than 1 is

/2x+1/>1
2X + 1 > 1 or 2x + 10 or 2x0 or X

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1. It is known that f (x) is an odd function defined on R, and when x > 0, f (x) = x (X-2), find the analytic expression of F (x). Note (X-2) is an absolute value
2. It is known that f (x) is an odd function defined on R. when x ≥ 0, f (x) = x2-2x, then the expression of F (x) on (- ∞, 0) is______ ．
3. It is known that the odd function f (x) defined on R satisfies f (x + 4) = - f (x) and is an increasing function in the interval [0,2]. If the equation f (x) = m (M > 0) has four different roots x1, X2, X3, X4 in the interval [- 8,8], then what is X1 + x2 + X3 + X4 equal to
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5. If f (x) is an even function defined on R with period of 3 and f (2) = 0, then the minimum number of solutions of the equation f (x) = 0 in the interval (0,6) is () A. 5B. 4C. 3D. 2
6. If it is known that the function f (x) defined on R is an odd function with period 2, then the equation f (x) has at least two properties in the interval [- 2,2]_____ A real number root If f (0) = 0, f (- 1) = - f (1) is obtained by odd function, and if f (2) = f (- 2) = f (0), f (1) = f (- 1) is obtained by period 2, then f (2) = f (- 2) = f (1) = f (- 1) = f (0) = 0, that is, there are at least five real roots I don't understand the answer“ So f (2) = f (- 2) = f (1) = f (- 1) = f (0) = 0 How can f (- 2) be equal to F (1) and f(-1) Where else do you get five real roots?
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11. If both a and B are integers, and the difference of equation AX2 + bx-2008 = 0 is prime, then the value of 3A + B is () A. 100B. 400C. 700D. 1000
12. It is known that P and Q are positive integers, and the two roots of the equation 7X2 PX + 2009q = 0 are prime numbers, then p + Q=______ ．
13. If M and N are positive integers and the two roots of equation 1 / 2mx ^ 2-1 / 2nx + 1999 = 0 are prime numbers, then 6m ^ 2 + n-1=
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