Given that a + B + C = 10 / 9, B-A = 1 / 2, B-C = 7 / 18, what are the numbers of a, B, C and C Please

Given that a + B + C = 10 / 9, B-A = 1 / 2, B-C = 7 / 18, what are the numbers of a, B, C and C Please

B-A=1/2
A=B-1/2
B-C=7/18
C=B-7/18
Substituting a + B + C = 10 / 9
B-1/2+B+B-7/18=10/9
3B=2
B=2/3
A=B-1/2=1/6
C=B-7/18=5/18