It is proved that if a and B are nonnegative real numbers, then a + B + 2 ≥ 2 (√ a + b)
a+b+2-2(√a+√b)
=a-2√a+1+b-2√b+1
=(√a-1)^2+(√b-1)^2
≥0
therefore
a+b+2≥2(√a+√b)
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