(1):(2X-Y-3)^2 (2):59.8*60.2 (3）198^2 （4）：4(X+1)^2-（2x+5）（2X-5） Questions 1, 2, 3 and 4 need integral calculation

1. The original formula = (2x-y) & sup2; - 2 (2x-y) × 3 + 9
= 4x²-4xy+y²-12x+6y+9
= 4x²+y²-4xy-12x+6y+9
2. The original formula is 59.8 × 60.2
=3599.96
3. The original formula is 198 & sup2;
=39204
4. The original formula = 4 × (X & sup2; + 2x + 1) - (4x & sup2; - 25)
=4x²+8x+4-4x²+25
=8x+29

RELATED INFORMATIONS

1. When x = 3, find the value of 3 / 4 [4 / 3 (x-1) - 8] - (- 2x-5 / 3)
2. 3 / 1-x + 2 / 2 = 1,3 / 2x-6 = 2 / x + 2 + 1,3 / x + 8 = - x, 3-1.2x = 5 / 4-12
3. General solutions of the system of equations x (1) + X (2) + X (3) + 2x (4) = 3 2x (1) - x (2) + 3x (3) + 8x (4) = 8 - 3x (1) + 2x (2) - 2x (3) - 9x (4) = - 5x (1) - 2x (2) - 3x (3) = - 4
4. When k is equal to what value, the solution of the equation about X is x = 1
5. If the solution of the equation 2x + 1 = 3 about X is the same as that of the equation 2-third K-X = 0, find the value of K. why do I calculate that all are equal to 4?
6. Given the quadratic function y = − 12x2 + X + 32, we can solve the following problems: (1) change the quadratic function into the form of y = a (X-H) 2 + K; (2) write the vertex coordinates and symmetry axis of the quadratic function
7. How to convert the quadratic function y = x ^ 2-2x + 3 to y = (X-H) ^ 2 + k
8. In the (1-2x) ∧ n expansion, the binomial coefficients of the fifth, sixth and seventh terms form an arithmetic sequence, and the constant term in the expansion is obtained
9. In the expansion of 1-2x) n, if the binomial coefficients of the second, third and fourth terms form an arithmetic sequence, then the fifth term is
10. In binomial expansion, the binomial coefficients of the second, third and fourth terms form an arithmetic sequence, and the constant term in the expansion can be obtained?
11. (x ^ 2 + 2x-8) / (x ^ 3 + 2x ^ 2 + x) / {(X-2) / X. (x + 4) / (x + 1) where x = 4 / 5
12. 8（1-X）-4（2X+3）=5(x-2)
13. X + 5 / 1 = 3 = 2 / 2 x
14. 3-x = 1 and 2 / 5, X=
15. Billy 0.3 1.5 = 4.2 x 2 1:4 = 10 1:x
16. (- 10) x [(- 1 / 5) + 1 / 2] = (- 10) x how much + how much x 2 / 1
17. 2 / 5 * x = 1 / 4 * (300-x) + 55. Write every step to solve the equation
18. X + 1.5 * 2 / 3 = 2
19. 1.2 of x = 4 of 5 (how to do it?) Please help me~
20. 1 / 2 [X-1 / 2 (x + 1)] ≤ 2 / 5 (x-1)