3-x = 1 and 2 / 5, X=

RELATED INFORMATIONS

• 1. X + 5 / 1 = 3 = 2 / 2 x
• 2. 8（1-X）-4（2X+3）=5(x-2)
• 3. (x ^ 2 + 2x-8) / (x ^ 3 + 2x ^ 2 + x) / {(X-2) / X. (x + 4) / (x + 1) where x = 4 / 5
• 4. (1):(2X-Y-3)^2 (2):59.8*60.2 (3）198^2 （4）：4(X+1)^2-（2x+5）（2X-5） Questions 1, 2, 3 and 4 need integral calculation
• 5. When x = 3, find the value of 3 / 4 [4 / 3 (x-1) - 8] - (- 2x-5 / 3)
• 6. 3 / 1-x + 2 / 2 = 1,3 / 2x-6 = 2 / x + 2 + 1,3 / x + 8 = - x, 3-1.2x = 5 / 4-12
• 7. General solutions of the system of equations x (1) + X (2) + X (3) + 2x (4) = 3 2x (1) - x (2) + 3x (3) + 8x (4) = 8 - 3x (1) + 2x (2) - 2x (3) - 9x (4) = - 5x (1) - 2x (2) - 3x (3) = - 4
• 8. When k is equal to what value, the solution of the equation about X is x = 1
• 9. If the solution of the equation 2x + 1 = 3 about X is the same as that of the equation 2-third K-X = 0, find the value of K. why do I calculate that all are equal to 4?
• 10. Given the quadratic function y = − 12x2 + X + 32, we can solve the following problems: (1) change the quadratic function into the form of y = a (X-H) 2 + K; (2) write the vertex coordinates and symmetry axis of the quadratic function
• 11. Billy 0.3 1.5 = 4.2 x 2 1:4 = 10 1:x
• 12. (- 10) x [(- 1 / 5) + 1 / 2] = (- 10) x how much + how much x 2 / 1
• 13. 2 / 5 * x = 1 / 4 * (300-x) + 55. Write every step to solve the equation
• 14. X + 1.5 * 2 / 3 = 2
• 15. 1.2 of x = 4 of 5 (how to do it?) Please help me~
• 16. 1 / 2 [X-1 / 2 (x + 1)] ≤ 2 / 5 (x-1)
• 17. X to 5 = 2 to 1 is 1 / 2
• 18. Real numbers x, y and Z satisfy x + y + Z + 8 = 2 √ (x-1) + 4 √ (Y-2) + 6 √ (Z-3). What is the value of X + y + Z?
• 19. If real numbers x and y satisfy the following conditions: x ^ (3 ^ 3 + 4 ^ 3) + y ^ (3 ^ 3 + 6 ^ 3) = 1, x ^ (5 ^ 3 + 4 ^ 3) + y ^ (5 ^ 3 + 6 ^ 3) = 1, then x + y = The answer is 432, but do not know the process, please be more detailed, please!
• 20. 11 (2) if real numbers x and y satisfy: X / (2 ^ 10 + 5 ^ 3) + Y / (2 ^ 10 + 6 ^ 3) = 1, X / (3 ^ 10 + 5 ^ 3) + Y / (3 ^ 10 + 6 ^ 3) = 1, then x + y= Let 2 ^ 10 and 3 ^ 10 be two real roots of the equation x / (T + 5 ^ 3) + Y / (T + 6 ^ 3) = 1 about t The equation x / (T + 5 ^ 3) + Y / (T + 6 ^ 3) = 1 can be obtained It is reduced to the general form of quadratic equation t^2+(5^3+6^3-x-y)t+…… =0 (the part of the ellipsis doesn't matter) According to the relationship between root and coefficient 2^10+3^10=x+y-5^3-6^3 So x + y = 2 ^ 10 + 3 ^ 10 + 5 ^ 3 + 6 ^ 3 my question is: "x + y = 2 ^ 10 + 3 ^ 10 + 5 ^ 3 + 6 ^ 3" this is the result? How many numbers does it equal? Do you want to calculate it hard?