Real numbers x, y and Z satisfy x + y + Z + 8 = 2 √ (x-1) + 4 √ (Y-2) + 6 √ (Z-3). What is the value of X + y + Z?

Real numbers x, y and Z satisfy x + y + Z + 8 = 2 √ (x-1) + 4 √ (Y-2) + 6 √ (Z-3). What is the value of X + y + Z?

x+y+z+8=2√(x-1)+4√(y-2)+6√(z-3)x+y+z+8-2√(x-1)-4√(y-2)-6√(z-3)=0(x-1)-2√(x-1)+1+(y-2)-4√(y-2)+4+(z-3)-6√(z-3)+9=0(√(x-1)-1)^2+(√(y-2)-2)^2+(√(z-3)-3)^2=0(√(x-1)-1)^2>=0,(√(y-2)-2)^2>=0,...

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