x-3x-8/2+1>=2(10-x)/7 I'm counting X
Take 14 on both sides
14x-7(3x-8)+14>=4(10-x)
-7x+70>=40-4x
3x
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- 1. x-(3x-8)/2
- 2. 7 / 1-8 + 3x = 3x-10-4
- 3. If real numbers x and y satisfy X / 2 ^ 5 + 5 ^ 3 + Y / 2 ^ 5 + 6 ^ 3 = 1, X / 3 ^ 5 + 5 ^ 3 + Y / 3 ^ 5 + 6 ^ 3 = 1, find x + y
- 4. x. If y and Z are real numbers and X + y + Z = 4 √ (x-3) + 3 √ (y-6) = 6 √ (Z-5), then x + y + Z =? X + y + Z = 4 √ (x-3) + 2 √ (y-6) + 6 √ (Z-5) a^2+b^2+c^2+14=4a+2b+6
- 5. 11 (2) if real numbers x and y satisfy: X / (2 ^ 10 + 5 ^ 3) + Y / (2 ^ 10 + 6 ^ 3) = 1, X / (3 ^ 10 + 5 ^ 3) + Y / (3 ^ 10 + 6 ^ 3) = 1, then x + y= Let 2 ^ 10 and 3 ^ 10 be two real roots of the equation x / (T + 5 ^ 3) + Y / (T + 6 ^ 3) = 1 about t The equation x / (T + 5 ^ 3) + Y / (T + 6 ^ 3) = 1 can be obtained It is reduced to the general form of quadratic equation t^2+(5^3+6^3-x-y)t+…… =0 (the part of the ellipsis doesn't matter) According to the relationship between root and coefficient 2^10+3^10=x+y-5^3-6^3 So x + y = 2 ^ 10 + 3 ^ 10 + 5 ^ 3 + 6 ^ 3 my question is: "x + y = 2 ^ 10 + 3 ^ 10 + 5 ^ 3 + 6 ^ 3" this is the result? How many numbers does it equal? Do you want to calculate it hard?
- 6. If real numbers x and y satisfy the following conditions: x ^ (3 ^ 3 + 4 ^ 3) + y ^ (3 ^ 3 + 6 ^ 3) = 1, x ^ (5 ^ 3 + 4 ^ 3) + y ^ (5 ^ 3 + 6 ^ 3) = 1, then x + y = The answer is 432, but do not know the process, please be more detailed, please!
- 7. Real numbers x, y and Z satisfy x + y + Z + 8 = 2 √ (x-1) + 4 √ (Y-2) + 6 √ (Z-3). What is the value of X + y + Z?
- 8. X to 5 = 2 to 1 is 1 / 2
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- 10. 1.2 of x = 4 of 5 (how to do it?) Please help me~
- 11. 3x-7/0.4 - x-0.5/0.5 - x/0.2=10?
- 12. 2.5x-0.5×8=6,x=? solve equations
- 13. Calculation: 10 / X - (10 / 2.5x) = 1.5
- 14. √5x^2-(5√2+1)x+√10=0
- 15. 4/5[5/4(x-4)+5x-10]+(0.1x-0.2)/0.1=x-2 0.1x/0.03-(0.9-0.2x)/0.7=1
- 16. X/2+10=5.5X-1
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- 18. (1-x)+(1-x)^2+(1-x)^3+…… +What is the coefficient of x ^ 2 in the expansion of (1-x) ^ 10
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