X to 5 = 2 to 1 is 1 / 2

x∶5=2∶3/2
∴3/2*x=5×2
3/2*x=10
∴x=10×2/3
∴x=20/3

RELATED INFORMATIONS

1. 1 / 2 [X-1 / 2 (x + 1)] ≤ 2 / 5 (x-1)
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3. X + 1.5 * 2 / 3 = 2
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5. (- 10) x [(- 1 / 5) + 1 / 2] = (- 10) x how much + how much x 2 / 1
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7. 3-x = 1 and 2 / 5, X=
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11. Real numbers x, y and Z satisfy x + y + Z + 8 = 2 √ (x-1) + 4 √ (Y-2) + 6 √ (Z-3). What is the value of X + y + Z?
12. If real numbers x and y satisfy the following conditions: x ^ (3 ^ 3 + 4 ^ 3) + y ^ (3 ^ 3 + 6 ^ 3) = 1, x ^ (5 ^ 3 + 4 ^ 3) + y ^ (5 ^ 3 + 6 ^ 3) = 1, then x + y = The answer is 432, but do not know the process, please be more detailed, please!
13. 11 (2) if real numbers x and y satisfy: X / (2 ^ 10 + 5 ^ 3) + Y / (2 ^ 10 + 6 ^ 3) = 1, X / (3 ^ 10 + 5 ^ 3) + Y / (3 ^ 10 + 6 ^ 3) = 1, then x + y= Let 2 ^ 10 and 3 ^ 10 be two real roots of the equation x / (T + 5 ^ 3) + Y / (T + 6 ^ 3) = 1 about t The equation x / (T + 5 ^ 3) + Y / (T + 6 ^ 3) = 1 can be obtained It is reduced to the general form of quadratic equation t^2+(5^3+6^3-x-y)t+…… =0 (the part of the ellipsis doesn't matter) According to the relationship between root and coefficient 2^10+3^10=x+y-5^3-6^3 So x + y = 2 ^ 10 + 3 ^ 10 + 5 ^ 3 + 6 ^ 3 my question is: "x + y = 2 ^ 10 + 3 ^ 10 + 5 ^ 3 + 6 ^ 3" this is the result? How many numbers does it equal? Do you want to calculate it hard?
14. x. If y and Z are real numbers and X + y + Z = 4 √ (x-3) + 3 √ (y-6) = 6 √ (Z-5), then x + y + Z =? X + y + Z = 4 √ (x-3) + 2 √ (y-6) + 6 √ (Z-5) a^2+b^2+c^2+14=4a+2b+6
15. If real numbers x and y satisfy X / 2 ^ 5 + 5 ^ 3 + Y / 2 ^ 5 + 6 ^ 3 = 1, X / 3 ^ 5 + 5 ^ 3 + Y / 3 ^ 5 + 6 ^ 3 = 1, find x + y
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17. x-(3x-8)/2
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19. 3x-7/0.4 - x-0.5/0.5 - x/0.2=10?
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