lim(1+4+7+… +(3n-2))/(7n^2-5n),
Summation of arithmetic sequence
1+4+7+… +(3n-2)=[1+(3n-2)]n/2=(3n^2-n)/2
lim(1+4+7+… +(3n-2))/(7n^2-5n)
=lim(3n^2-n)/(14n^2-10n)
=3/14
RELATED INFORMATIONS
- 1. limn→∞[11•4+14•7+17•10+… +1(3n−2)(3n+1)]=______ .
- 2. Fill in the blanks LIM (n →∞) = √ (3N ^ 2 + 6N + 5) / (3n-2)=____ How to calculate this problem?
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- 4. Finding function limit LIM (Sinn) / n Finding function limit LIM (n!) / N ^ n N tends to infinity Why?
- 5. Find function limit LIM (n-1) * 2 ^ n, n tends to be positive infinity
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- 11. Find the following limit, Lim e ^ (1 / 2x), X → 0 Please give the specific steps,
- 12. The calculation limit is 2 / X of LIM (n →∞) (1 + 2x) (x→∞)
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- 14. lim(x→0)((arctan(x∧2))╱(sin(x╱2)sinx))
- 15. Can x → 0 Lim arctan (SiNx / x) be written as arctan LIM (SiNx / x)? Can Lim ln (SiNx / x) be written in this form? Why?
- 16. Find Lim e ^ (1 / x ^ 2) * arctan ((x ^ 2 + 2-1) / (x + 1) * (X-2)) when x approaches 0, - 1,2
- 17. What does the negative direction of LIM x tend to be 1 arctan [1 / ln (1-x)] equal to
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- 19. lim(x→+∞) (2/π arctan X)^X
- 20. Find the limit Lim ┬ (x → 0) &; ((Tan &; x-sin &; x) / ln &; (1 + x ^ 3)) lim┬(x→0)〖(x-sinx)/x^3 〗