Lim（(1²＋2²＋…… ＋n²)/n³）n→∞＝

1²＋2²＋…… ＋n²=n(n+1)(2n+1)/6
So the original formula = limn (n + 1) (2n + 1) / 6N ^ 3
=lim(1+1/n)(2+1/n)/6
=1*2/6
=1/3

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