F (x) = logx / X for the first and second derivatives Dizzy.. Every answer is heavy.

Logx your base is not very clear, I use a instead of log (a) x to express the logarithm f '(x) = (1 / xlna * x-logx) / X & sup2; = (1 / LNA log (a) x) / X & sup2; f' (x) = [- 1 / xlna * X & sup2; - (1 / 1NA log (a) x) * 2x] / x ^ 4 = [- 3 / LNA + 2lo

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