It is proved that the derivative of F (x) * LNX + F (x) * (2 / x) = 0

f‘（x）=-f（x）* （2/xlnx）
df(x)/f(x)=2dx/xlnx
The integral is: LNF (x) = 2lnx + lnc
f(x)=C(lnx)^2

RELATED INFORMATIONS

1. Let g (x) = {① e ^ x, X ≤ 0, ② LNX, x > 0, then the solution set of inequality g (x) ≤ 1 about X is () A.（-∞,1] B.(-∞,e] C.[o,e] D.[0,1]
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