lim(x(sin)^2)

What does x tend to be?

RELATED INFORMATIONS

1. Lim sin (x-1) / X-1 x tends to infinity
2. How much is SiNx, sin (1 / x), sin (x ^ 2) equal when Lim x approaches zero? And how much are they equal when Lim x approaches infinity? And how much is cos Tan in this case?
3. lim(x->0)[(x^2)*sin(1/x)]/sinx I use the equivalent infinitesimal, because when (x - > 0), SiNx ~ x, so sin (1 / x) ~ 1 / x, Then the original formula = LIM (x - > 0) (x ^ 2) * (1 / x) / SiNx = 1, right
4. LIM (x tends to infinity) (sin n) / N =?
5. lim（x→2）x-2 /sin(
6. lim(sin√(x+1)-sin√x) x→+∞
7. LIM (x tends to 0) x ^ 2 / (sin ^ 2) * x / 3
8. lim（x→1）sinπx╱2（x-1）
9. LIM (sin △ X / 2) / △ x is a 1 / 2 proof process when △ x tends to zero
10. [mathematical analysis] proves that LIM ∫ (sin (x)) ^ n = 0 The book emphasizes that if the mean value theorem is used, then there should be ξ_ n→π/2 In the end, it shows that for 0
11. Find Lim X - > ∞ (xtan2 / x + (1 / x ^ 2) * (SIN) x ^ 2)
12. lim(x---1)[sin^2(x)-sin^2(1)]/[x-1]=? University Advanced Mathematics, seek advice
13. Find Lim sin (x-1) / (x ^ 2-1) where X - > 1
14. Detailed process of LIM (x → 1) lncos (x-1) / (1-sin (π X / 2))
15. Limit: LIM (x - > 4) (x ^ 2-6x + 8) / (x ^ 2-5x + 4)
16. Finding limit LIM (x ^ 2-6x + 8) / x ^ 2 + X-6
17. 1.5 find the limit LIM (x → 4) (x ^ 2-6x + 8) / (x ^ 2-5x + 4) 1.5 find the limit LIM (x → 4) (x ^ 2-6x + 8) / (x ^ 2-5x + 4)
18. Help find a limit: LIM (x ^ 2-6x + 8) / (x ^ 2-5x + 4) x → 4
19. lim x→∞ x^2-6x+8/x^2-5x+4 Wrong. It's not infinity. It's four
20. Prove LIM (X -- > x0) 2 ^ x = 2 ^ x0 by definition