Help find a limit: LIM (x ^ 2-6x + 8) / (x ^ 2-5x + 4) x → 4

RELATED INFORMATIONS

• 1. 1.5 find the limit LIM (x → 4) (x ^ 2-6x + 8) / (x ^ 2-5x + 4) 1.5 find the limit LIM (x → 4) (x ^ 2-6x + 8) / (x ^ 2-5x + 4)
• 2. Finding limit LIM (x ^ 2-6x + 8) / x ^ 2 + X-6
• 3. Limit: LIM (x - > 4) (x ^ 2-6x + 8) / (x ^ 2-5x + 4)
• 4. Detailed process of LIM (x → 1) lncos (x-1) / (1-sin (π X / 2))
• 5. Find Lim sin (x-1) / (x ^ 2-1) where X - > 1
• 6. lim(x---1)[sin^2(x)-sin^2(1)]/[x-1]=? University Advanced Mathematics, seek advice
• 7. Find Lim X - > ∞ (xtan2 / x + (1 / x ^ 2) * (SIN) x ^ 2)
• 8. lim(x(sin)^2)
• 9. Lim sin (x-1) / X-1 x tends to infinity
• 10. How much is SiNx, sin (1 / x), sin (x ^ 2) equal when Lim x approaches zero? And how much are they equal when Lim x approaches infinity? And how much is cos Tan in this case?
• 11. lim x→∞ x^2-6x+8/x^2-5x+4 Wrong. It's not infinity. It's four
• 12. Prove LIM (X -- > x0) 2 ^ x = 2 ^ x0 by definition
• 13. LIM (x tends to positive infinity) cosx / [e ^ x + e ^ (- x)] =?
• 14. f(x)=ln(x+1),lim(x->0)
• 15. F (x) = x ^ 2 - ax + ln (x + 1), a belongs to R 0 F extremum when a = 2 If the function f (x) always has f prime (x) greater than x in the interval (0,1), find the value range of real number a The word "0" doesn't mean The speed of copying is fast
• 16. Given function f (x) = ln (AX) / (x + 1) - ln (AX) + ln (x + 1) Given the function f (x) = ln (AX) / (x + 1) - ln (AX) + ln (x + 1), (a is not equal to 0 and R) 1. Find the definition field of function f (x) 2. Find the monotone interval of function f (x) 3. When a > 0, if there is x such that f (x) ≥ ln (2a) holds, the value range of a is obtained
• 17. Ln x = ax has several real roots (a > 0)
• 18. Find Lim x → 0 (Tan 2x SiNx) / X and lim x → 0 (COS x-cos 3x) / x ^ 2
• 19. Is the square of LIM x → 0 (cosx-cos3x) / X equal to? Lim x → 0 (cosx-cos3x) / x square, please write the steps!
• 20. The limit of tanx-6 / secx + 5 when x tends to Π / 2