The limit of tanx-6 / secx + 5 when x tends to Π / 2

The limit of tanx-6 / secx + 5 when x tends to Π / 2

lim(x→π/2)[(tanx-6)/(secx+5)]
=lim(x→π/2)[sinx-6cosx)/(1+5cosx)]
=(1-6×0)/(1+5×0)
=1