Given the function f (x) = 2ln3x + 8x, the value of LiMn →∞ f (1 − 2 △ x) − f (1) △ x is () A. 10B. -10C. -20D. 20

∵ f ′ (x) = 63x + 8, ∵ Lim △ x → 0f (1 − 2 △ x) − f (1) △ x = − 2lim − 2 △ x → 0f (1 − 2 △ x) − f (1) − 2 △ x = - 2F ′ (1) = - 2 × (63 + 8) = - 20

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