10. Let a > 0, b > 0, e be the base of natural logarithm 10. Let a > 0, b > 0 and E be the base of natural logarithm A. If EA + 2A = EB + 3b, then a > B B. If EA + 2A = EB + 3b, then a < B C. If ea-2a = eb-3b, then a > B D. If ea-2a = eb-3b, then a < B A B after e is the index

10. Let a > 0, b > 0, e be the base of natural logarithm 10. Let a > 0, b > 0 and E be the base of natural logarithm A. If EA + 2A = EB + 3b, then a > B B. If EA + 2A = EB + 3b, then a < B C. If ea-2a = eb-3b, then a > B D. If ea-2a = eb-3b, then a < B A B after e is the index

A. D. A, B, a / b = (E + 3) / (E + 2) > 1, that is a > B
Similarly, a / b = (E-3) / (E-2) can be obtained after C and D are shifted