2 (- cos (π / 6) + isin (π / 6)) = 2 (COS (π - π / 6) + isin (π - π / 6)) why is π - π / 6? Who can tell me

2 (- cos (π / 6) + isin (π / 6)) = 2 (COS (π - π / 6) + isin (π - π / 6)) why is π - π / 6? Who can tell me

-cosa=cos(π-a)
sina=sin(π-a)