It is proved that the nth power of (1 + cos θ + isin θ) = the nth power of 2 times the nth power of cos θ / 2 (COS n θ / 2 + isin n n θ / 2) Such as the title
Your result is wrong. You need to know the following formula, so
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- 11. 2 (- cos (π / 6) + isin (π / 6)) = 2 (COS (π - π / 6) + isin (π - π / 6)) why is π - π / 6? Who can tell me
- 12. How is cos (x) * cos (π / 6-x) = 1 / 2 * [cos (π / 6) + cos (2x - π / 6)] derived?
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- 16. Is there a similar formula for 1 / cos & # 178; X = sec & # 178; X?
- 17. The formula Sin & # 178; π / 2 = cos & # 178; π / 2=
- 18. What are the formulas of Sin & # 178; α = (1-cos (2 α)) / 2 and Sin & # 178; α = (1-sin (2 α)) / 2
- 19. Sin & # 178; X =? Cos & # 178; =? Theorem formula
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