A copper block weighing 48.06n is completely immersed in water. What is the buoyancy received. (P copper = 8.9 * 10 to the third power of kg / m, G is 10N / kg) How and why
From g = mg = ρ VG, the volume of copper block is obtained as follows:
V=G/(ρg)=48.06/(8.9*10^3*10)=5.4*10^-4m^3
When the copper block is completely immersed in water, the buoyancy is as follows:
F floating = ρ water GV = 1.0 * 10 ^ 3 * 10 * 5.4 * 10 ^ - 4 = 5.4n
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