Given x = log (2a) a, y = log (3a) 2a, prove 2 ^ 1-xy = 3 ^ y-xy. (PS: () is the base)

Given x = log (2a) a, y = log (3a) 2a, prove 2 ^ 1-xy = 3 ^ y-xy. (PS: () is the base) analytic: ∵ x = log (2a, a), y = log (3a, 2a) xy = LNA / ln (2a) * ln (2a) / ln (3a) = LMA / ln (3a) 1-xy = Ln3 / ln (3a), y-xy = LN2 / ln (3a) 2 ^ 1-xy = 2 ^ [Ln3 / ln (3a)] 3 ^ y-xy = 3 ^ [...]

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