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Derivation of higher numbers Y = ln (x + radical x ^ 2 + A ^ 2) Why not take 2x in the first step?
For the derivation of such a composite function, we must use the chain rule step by step. Here y = ln [x + √ (X & # 178; + A & # 178;)] you first think x + √ (X & # 178; + A & # 178;) is u, then y = LNU, and u = x + √ (X & # 178; + A & # 178;) for y to x derivation, y '= D (LNU) / Du * Du / DX obviously D (LNU
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