How to find the sum function of power series N = 0 to ∞Σ x ^ n / (n + 1)

F (x) = ∑ x ^ n / (n + 1) XF (x) = ∑ [x ^ (n + 1)] / (n + 1) [XF (x)] '= ∑ x ^ n, so [XF (x)]' = 1 / (1-x) so XF (x) = ∫ 1 / (1-x) DX = - ln (1-x) f (x) = - [ln (1-x)] / X

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