Solution 3 (SiNx) ^ 2-sinxcosx-2 (cosx) ^ 2 = 1

3 (SiNx) ^ 2-sinxcosx-2 (cosx) ^ 2 = 13sin ^ 2x-sinxcosx-2cos ^ 2x = sin ^ 2x + cos ^ 2x2sin ^ 2x-sinxcosx-3cos ^ 2x = 0 (2sinx-3cosx) (SiNx + cosx) = 02sinx = 3cosx or SiNx = - cosx. = > TaNx = 3 / 2 or TaNx = - 1. = > x = k π + arctan (3 / 2) or x = - π / 4 + K π

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1. The equation SiNx + cosx = a for X is known (1) If the equation has a real solution, find the value range of real number a (2) If the equation has two different real number solutions when x ∈ [0, π], find the value range of real number a and the sum of two real number solutions [- radical 2, + radical 2]; π / 2 The second problem I did was π Please write the detailed process and thinking
2. If the square of SiNx + cosx + k = 0 has a solution, then the value range of constant k is small
3. The image of the quadratic function y = 2 / 3x & # 178; is shown in the figure. The point A0 is at the origin of the coordinate, the points A1, A2, A3... A2010 are on the positive half axis of the Y axis, the points B1, B2, The image of the quadratic function y = 2 / 3x & # 178; is shown in the figure. The point A0 is at the origin of the coordinate, the points A1, A2, A3... A2014 are on the positive half axis of the y-axis, and the points B1, B2, B3,... B2014 are on the image of the quadratic function y = 2 / 3x & # 178; in the first quadrant, △ a0b1a1, △ a1b2a2, △ a2b3a3,... A2013b2014 are equilateral triangles, then the side length of △ a2013b2014 is equal=
4. Quadratic function y = (2 / 3) x ^ 2 image is above X axis, vertex coordinates (0,0) are origin A0, points A1, A2, A3 , A2008 on the positive half axis of y-axis, points B1, B Quadratic function y = (2 / 3) x ^ 2 image is above X axis, vertex coordinates (0,0) are origin A0, points A1, A2, A3 , A2008 on the positive half axis of y-axis, points B1, B2, B3 If the triangle a0b1a1, a1b2a2, a2b3a3 and a2007b2008a2008 are equilateral triangles, what is the side length of the triangle a2007b2008a2008?
5. Given that f (x) = x, G (x) = RF (x) + SiNx is a decreasing function on the interval [- 1,1] Finding the maximum of R
6. Monotone increasing interval of function y = xcosx SiNx
7. If the image of odd function y = f (x) is translated by two units along the positive direction of X axis, the resulting image is C. If C1 and C are symmetric about the origin, then C1 corresponds to the function
8. After the image of the function y = 3 / x + A is shifted one unit to the left, the image C1 of y = f (x) is obtained. If the curve C1 is symmetric about the origin, then the value of real number a is
9. Given the function FX = 2sinxcosx-2cos ^ 2x + 1, the image of the function FX is shifted to the right by 6 units to get GX
10. The image of the function f (x) = - 2cos (x + π / 4) is shifted a (a > 0) units to the left to get the image of the function y = g (x). If G (x) is an even function, then the image of a is a The minimum value is? Answer in detail, O (∩)_ Thank you
11. If x is the minimum internal angle of a triangle, then the maximum value of the function y = SiNx + cosx + sinxcosx is () A. -1B. 2C. −12+2D. 12+2
12. Is SiNx = 1 symmetric about the origin? What about cosx = 1? Why?
13. The minimum positive period of y = (SiNx cosx) / (SiNx + cosx) Write the detailed steps, online, etc. thank you
14. What is the minimum positive period of y = (SiNx cosx) ^ 2-1?
15. Let x ~ n (0.1) be a random variable and find the probability density of y = 4-x ^ 2
16. Let x ~ n (0,1), y = x & # 178;, find the probability density of Y
17. Let x ~ n (0,1) be a random variable and find the probability density of y = x ^ 2
18. Let the probability density of continuous random variable X be f (x) = {SiNx, 0 ≤ x ≤ a (previous line) 0, others (next line after braces). Try to determine the constant a and find P (x > π / 6)
19. Let x ~ n (0,1), find the probability density of y = 2x ^ 2 + 1 RT
20. Random variable x ~ n (2,0.1), then a. σ = 0.1, B. the image of probability density function is symmetric with respect to x = radical 2, C. μ = 2, D. φ (0) 2