The circle x * 2 + y * 2 + DX + ey + F = 0 (d * 2 + e * 2-4f > 0) is symmetric with respect to the straight line y = x + 1. The correct conclusion is d + e = 2 D + e = 1 D-E = 2 d-e=-

It is easy to know that the center of the circle (- D / 2, - E / 2) is on the straight line y = x + 1, so - E / 2 = - D / 2 + 1, so D-E = 2

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