If three points a (2,2), B (a, 0), C (0, b) (AB ≠ 0) are collinear, then the value of 1A + 1b is equal to______

AB = (A-2, - 2), AC = (- 2, b-2), according to the meaning of the question, ab ‖ AC has (A-2) · (b-2) - 4 = 0, that is ab-2a-2b = 0, so 1A + 1b = 12, so the answer is 12

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