A series of general terms and summation problem! If the sequence {an} is an arithmetic sequence with tolerance of 1 / 2, and the sum of the first 100 items is 145, then A2 + A4 + A6 + +a100=? 3Q!

From the fact that the sequence {an} is an arithmetic sequence with tolerance of 1 / 2, A1 = A2-1 / 2A3 = a4-1 / 2a5 = a6-1 / 2 A95 = a96-1 / 2A97 = a98-1 / 2a99 = a100-1 / 2, the sum of the first 100 items is 145, that is: S100 = a1 + A2 + a3 + A4 + A5 + +A97 + A98 + A99 + A100 = 145 A97, A99 with a

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