If f ′ (x0) = - 3, then limh → 0f (x0 + H) - f (x0-h) H = () A. -3B. -6C. -9D. -12

If f ′ (x0) = - 3, then limh → 0f (x0 + H) - f (x0-h) H = () A. -3B. -6C. -9D. -12

Then limh → 0f (x0 + H) - f (x0-h) H = limh → 0f (x0 + H) - f (x0) + F (x0) - f (x0-h) H = limh → 0f (x0 + H) - f (x0) H + lim-h → 0f (x0-h) - F (x0) - H = 2F ′ (x0) = - 6