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If f (3 ^ x) = 2x * log2 ^ 3, then the value of F (2 ^ 1005) is equal to,
If it is log & # 8322; 3, the solution is as follows: let y = 3 ^ x, then x = Log & # 8323; y f (3 ^ x) = 2x * Log & # 8322; 3 can be changed into: F (y) = 2log & # 8323; ylog & # 8322; 3 f (2 ^ 1005) = 2log & # 8323; 2 ^ 1005log & # 8322; 3 = 2 * 1005 * Log & # 8323; 2log & # 8322; 3 = 2010
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