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Let x → 0, etanx ex and xn be infinitesimals of the same order, then n is () A. 1B. 2C. 3D. 4
∵ TaNx = x + 13x3 + O (x3) & nbsp; etanx-x-1 ～ tanx-x ∵ etanx − ex = ex (etanx − x − 1) = 13x3 + O (x3) ∵ etanx ex and X3 are non equivalent infinitesimals of the same order ∵ n = 3, so C
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