How to simplify SiNx ^ 4 + cosx ^ 2

In this way, SiNx ^ 4 + cosx ^ 2 = SiNx ^ 4 + 1-sinx ^ 2 = SiNx ^ 2 (SiNx ^ 2-1) + 1 = SiNx ^ 2 (- cosx ^ 2) + 1 = - 1 / 4sin2x ^ 2 + 1 = - 1 / 4 ((1-cos4x) / 2) + 1 = - 1 / 8 (1-cos4x) + 1 = 1 / 8 (cos4x) + 7 / 8. The main idea is to use SiNx ^ 2 + cosx ^ 2 = 1 and cos2x = 1-2sinx

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