In the arithmetic sequence {an}, d = 12, S100 = 145, then a1 + a3 + A5 + +The value of A99 is () A. 57B. 58C. 59D. 60

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• 1. The tolerance of arithmetic sequence an d = 1 / 2, and S100 = 145, find a1 + a3 + A5 +. + A99 Why: M2 = A2 + A4 + A6 +... + A100 = a1 + a3 + A5 +... + A99 + (1 / 2) × 50 How does this (1 / 2) × 50 come from?
• 2. It is known that {an} is an arithmetic sequence with a tolerance of 2, and A1, A3 and A4 are proportional sequences, then the sum of the first nine terms of the sequence {an} is equal to () A. 0B. 8C. 144D. 162
• 3. Known: in the arithmetic sequence {an}, A3 + A4 = 15, a2a5 = 54, tolerance d < 0 Find the maximum value of [Sn - (an-3)] / N and the corresponding value of n Ans:n=4 In this case, ymax = 15 / 2
• 4. Known: in the arithmetic sequence {an}, A3 + A4 = 15, a2a5 = 54, tolerance d < 0, the second question 1) Finding the general term formula an of sequence {an} 1、 The arithmetic sequence is A2 + A5 = A3 + A4 = 15 a2a5=54 By Weida theorem A2, A5 are the equations X & # 178; - 15x + 54 = 0 x=6,x=9 d
• 5. If A2 = 1, A3 = 3, then S4 = () A. 12B. 10C. 8D. 6
• 6. If A2 + a3 = 4, then S4=
• 7. If A2 = 1, A3 = 3, then S4=______ ．
• 8. If the cubic power of 4x minus the square of 2x, the quadratic power of Y minus the square of N plus the quadratic power of Y is a quartic polynomial, find the cubic power of half n (n-1) + 3N If the cubic power of 4x-2x is a quartic polynomial, the cubic power of half n (n-1) + 3N can be obtained
• 9. If there are three common forces of 3N, 5N and 6N, then their resultant force () A. It may be zero. B. it may not be zero. C. the resultant force must be in the direction of 6N. D. the resultant force must be opposite to the direction of 3N
• 10. If the three forces are 5N, 3N and 7n respectively, the maximum of their resultant force is?
• 11. If the tolerance of arithmetic sequence {an} d = 1 / 2, a1 + A2 + a3... + A99 = 60, calculate S100
• 12. Given that the sequence {an} is an arithmetic sequence, the sum of the first n terms Sn = n ^ 2, find the value of a1 + a3 + A5 + A7 +. + a25
• 13. Given that the sum of the first n terms of the arithmetic sequence {an} is Sn = 2n & # 178; - 10N, find the values of (1) A1 and A3; (2) find A5 + A6 + A7 + A8; (3) find its general term formula and judge whether it is arithmetic sequence
• 14. Only the first N-term sum formula of the sequence {an} is Sn = (3) ^ n - 1, the general term formula of {an} is obtained, and it is proved that {an} is an equal ratio sequence
• 15. In the equal ratio sequence {an}, if a1 + A2 + a3 = 7, a1a2a3 = 8, and the common ratio is greater than 1, find the first sequence N and Sn of the sequence
• 16. Given that the sequence {an} satisfies A1 = 1, an + 1 = 2An + 1 (n ∈ n +), (1) let BN = an + 1, prove that the sequence {BN} is an equal ratio sequence; (2) find the expression of an
• 17. If the first n terms of positive term sequence {an} and Sn satisfy 10sn = an ^ 2 + 5An + 6, and A1, A3, A15 are equal proportion sequence, then A2010=
• 18. Given positive sequence {an}, the first n terms and Sn satisfy 10sn = an ^ 2 + 5An + 6, and A1, A3, A15 are equal proportion sequence, (1) find the general term of sequence {an} (the general term is an = 5n-3) (2) let BN = 2 / [an * a (n + 1)], Sn is the sum of the first n terms of sequence {BN}, find SN
• 19. Given the positive term sequence {an}, the first n terms and Sn satisfy 10sn = an2 + 5An + 6, and A1, A3, A15 are equal proportion sequence, find the general term an of the sequence {an}
• 20. Given the positive term sequence {an}, the first n terms and Sn satisfy 10sn = an2 + 5An + 6, and A1, A3, A15 are equal proportion sequence, find the general term an of the sequence {an}