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If there are p prime numbers, Q composite numbers, s even numbers and t odd numbers in the first n natural numbers, then (P-T) + (Q-S) =? Strive to be specific
Because n natural numbers must be odd or even, so S + T = n
In natural numbers above 2, they must be composite or prime, so p + q = n-1 (1 is neither prime nor composite)
So (P-T) + (Q-S) = (P + Q) - (T + s) = - 1
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