Let {an} be an arbitrary equal ratio sequence, and the sum of the first n terms, the sum of the first 2n terms and the sum of the first 3N terms are x, y and Z respectively. Then () A. X+Z=2YB. Y(Y-X)=Z(Z-X)C. Y2=XZD. Y(Y-X)=X(Z-X)

Let {an} be an arbitrary equal ratio sequence, and the sum of the first n terms, the sum of the first 2n terms and the sum of the first 3N terms are x, y and Z respectively. Then () A. X+Z=2YB. Y(Y-X)=Z(Z-X)C. Y2=XZD. Y(Y-X)=X(Z-X)

Take the equal ratio sequence 1, 2, 4, let n = 1, then x = 1, y = 3, z = 7 are substituted into the checking calculation, only option D is satisfied, so select D