It is known that {an} is an arithmetic sequence, A1 = 2, A2 = 3. If three numbers are inserted between every two adjacent terms to form a new arithmetic sequence with the number of the original sequence, we can find: (1) what is the 12th term of the original sequence? (2) What is the 29th item of the new sequence?

It is known that {an} is an arithmetic sequence, A1 = 2, A2 = 3. If three numbers are inserted between every two adjacent terms to form a new arithmetic sequence with the number of the original sequence, we can find: (1) what is the 12th term of the original sequence? (2) What is the 29th item of the new sequence?

(1) A {an} is an arithmetic sequence, A1 = 2, A2 = 3. If three numbers are inserted between every two adjacent terms to form a new arithmetic sequence with the number of the original sequence, it can be recorded as {BN}, then the arithmetic sequence {BN} is a sequence with 2 as the first term and 3 as the fifth term. Let the tolerance of {an} be D, and let the tolerance of {BN} be d ', then 2 + D = 3, 2 + 4D ′ = 3, and the solution is d = 1, D ′ = 14, so the general term of the original arithmetic sequence {an} is : an = 2 + 1 × (n-1) = n + 1, the general term of the new arithmetic sequence {BN} is: BN = 2 + 14 (n − 1) = n + 74, so the 12th term of the original sequence is A12 = 13, let BN = 13, solve N = 45, so the 12th term of the original sequence is the 45th term of the new sequence. (2) from (1), we know that the 29th term of the new sequence is B29 = 29 + 74 = 9, let an = 9 solve N = 8, so the 29th term of the new sequence is the 8th term of the original sequence