![](data:image/svg+xml;utf8,<svg xmlns="http://www.w3.org/2000/svg" xmlns:xlink="http://www.w3.org/1999/xlink" viewBox="0 0 72 71" width="72"></svg>)
The first step: take a natural number N1 = 5, calculate N1 + 1 to get A1; the second step: calculate the sum of all numbers of A1 to get N2, and calculate the square of N2 + 1 to get A2· V step 1: take a natural number N1 = 5, calculate the square of N1 + 1 to get A1; step 2: calculate the sum of all numbers of A1 to get N2, and calculate the square of N2 + 1 to get A2· Step 3: calculate the sum of the numbers of A2 to get N3, and then calculate the square of N2 The first step: take a natural number N1 = 5, calculate the square of N1 + 1 to get A1; the second step: calculate the sum of all numbers of A1 to get N2, and calculate the square of N2 + 1 to get A2· Step 3: calculate the sum of the numbers of A2 to get N3, and then calculate the square of N2 to get A3... And so on, then A2010 =?
n1=5,a1=5*5+1=26,
n2=2+6=8,a2=8^2+1=65,
n3=6+5=11,a3=11^2+1=122,
n4=1+2+2=5=n1,
therefore
n1,n2,n3,n4,n5,n6,...
namely
5,8,11,5,8,11,5,8,11,5,8,11,...
2010=3*670
therefore
n2010=n3=11
a2010=a3=65
RELATED INFORMATIONS
- 1. The first step is to take a natural number N1 = 5 and calculate the square 1 + 1 of n to get A1; the second step is to calculate the sum of the digits of A1 to get N2 and calculate the square 2 + 1 of n to get A2; Step 3: calculate the sum of the digits of A2 to get N3, and calculate the square 3 + 1 of n to get A3; '; then A2010 =?
- 2. The first step: take a natural number N1 = 5, calculate the square of N1 + 1 to get A1; the second step: calculate the sum of all numbers of A1 to get N2, and calculate the square of N2 + 1 to get A2 Step 3: calculate N3 of the sum of the numbers of A2, and then calculate the square of N3 to get A3 a2011=?
- 3. Step 1: take a natural number N1 = 5, calculate the square of N1 + 1 = A1. Step 2: calculate the sum of all the numbers of A1 to get N2, The first step: take a natural number N1 = 5, calculate N1 square + 1 = A1 Step 2: calculate the sum of the numbers of A1 to get N2, and calculate the square of N2 + 1 to get A2 Step 3: calculate the sum of the numbers of A2 to get N3, and calculate N3 square + 1 to get A3 …… And so on, A2012=______ .
- 4. 3、 Step 1: take a natural number N1 = 5, calculate the quadratic power + 1 of N1 to get α 1; step 2: calculate the sum of the numbers of α 1 to get N2, calculate the quadratic power + 1 of N2 to get α 2; step 3: calculate the sum of the numbers of α 2 to get N3, and then calculate the quadratic power + 1 of N3 to get α 3 By analogy, α 2011 = ()
- 5. The difference between the reciprocal of two consecutive odd numbers is 2 / 143. What are the reciprocal of these two consecutive odd numbers?
- 6. The difference between the reciprocal of two consecutive odd numbers is 2 / 143. What are the reciprocal of these two consecutive odd numbers To explain,
- 7. The reciprocal difference between two consecutive odd numbers is 2 / 143. What are the two numbers?
- 8. The difference between the reciprocal of two consecutive odd numbers is 2 / 143. What is the reciprocal of these two consecutive odd numbers?
- 9. If the difference between the reciprocal of two consecutive odd numbers is 2255, then the two consecutive odd numbers are () A. 13，15B. 15，17C. 17，19D. 19，21
- 10. The difference between the reciprocal of two natural numbers is one twelfth. What are the two numbers?
- 11. Step 1: take a natural number N1 = 5, calculate the square of N1 plus 1 to get A1; step 2: calculate the sum of all numbers of A1 to get N2, calculate the square of N2 plus 1 to get A2 Three steps: calculate the sum of the numbers of A2 to get N3, and add 1 to the square of N3 to get A3
- 12. It is proved that √ A & sup2; + B & sup2; + C & sup2; / 3 ≥ a + B + C / 3 ≥ & sup3; √ ABC (where a, B, C ∈ positive real numbers, and each pair is unequal),
- 13. Let a, B, C be real numbers, and prove: A & sup2; B & sup2; + B & sup2; C & sup2; + A & sup2; C & sup2; ≥ ABC (a + B + C)
- 14. Let a and B be natural numbers and satisfy 11 / A + B / 3 = 17 / 33, then a + B = ()
- 15. Compare the fractions n / M and n-a / M-A (m, N, a, are all non-zero natural numbers)
- 16. If the natural number AB satisfies 1 / A-1 / b = 1 / 182 and a: B = 7:13, what is the sum of a + B Why is this 13 / 7b-1 / b = 1 / 182 Here is (13-7) / 7b = 1 / 182 Why (13-7) / 7b = 1 / 182 The process should be very detailed,
- 17. M. N is a non-zero natural number, and 1 / M-1 / N = 2 / 143, M + n = () how to do
- 18. Natural numbers m, n satisfy m + n = 1991, prove: 10 ^ m + 10 ^ n is a multiple of 11? Who knows?
- 19. How many squares are there in natural numbers 100 to 200?
- 20. How to calculate the sum of incomplete squares of 100 natural numbers from 1 to 100?