![](data:image/svg+xml;utf8,<svg xmlns="http://www.w3.org/2000/svg" xmlns:xlink="http://www.w3.org/1999/xlink" viewBox="0 0 72 71" width="72"></svg>)
Put 1, 2, 3 These 100 natural numbers are randomly divided into 50 groups with two numbers in each group. Now, any one of the two numbers in each group is recorded as a and the other as B , which can be substituted into the algebraic formula 1 / 2 (| A-B | + A + b) for calculation, and the results can be obtained. After 50 groups of substitution, 50 values can be obtained, and the maximum value of sum can be obtained
The value of 1 / 2 (| A-B | + A + b) is equal to the larger one of a and B
The original problem is to divide 1 ~ 100 into 50 groups and find the maximum sum of the larger one in each group
The biggest is 51 to 100, of course
There's nothing wrong with this problem. It's a little interesting to find the minimum
RELATED INFORMATIONS
- 1. Put 1,2,3 The 100 natural numbers are randomly divided into 50 groups with two numbers in each group. Now, one of the two numbers in each group is recorded as a and the other as B Take it into algebraic formula 1 / 2 (a + B - | A-B |) to calculate and get the result. After 50 groups are brought in, you can get 50 values, and find the [minimum value] of the sum of these 50 values
- 2. Put 1, 2, 3 The 100 natural numbers are randomly divided into 50 groups with two numbers in each group. Now, mark any number in each group as a and the other as B, and substitute them into the algebraic formula 0.5 (| A-B | + A + b) to calculate the result. After 50 groups of numbers are substituted, 50 values can be obtained, and the maximum sum of these 50 values can be obtained
- 3. Divide the 100 natural numbers 1,2,3,4 ······ 100 into 50 groups with two numbers in each group. First, record any number of the two numbers in each group as a The other is denoted as B, which is substituted into the algebraic formula 1 / 2 (| a + B | + A + b) to calculate the result. After 50 groups are substituted, 50 results can be obtained, and the maximum value of these 50 values can be obtained
- 4. The 100 natural numbers 1,2,3, ·······, 100 are randomly divided into 50 groups, each group has two numbers, one of which is recorded as a, the other as B, Substituting into the algebraic formula # (189); (a + b-la-bl), we can get the result. After 50 groups are substituted, we can get 50 values, and find the minimum value of the sum of these 50 values (briefly explain the reason)
- 5. Put 1, 2, 3 The 100 natural numbers, 100, are randomly divided into 50 groups with two numbers in each group. Now, record any value of the two numbers in each group as a and the other as B, and substitute them into the algebraic formula 12 (| A-B | + A + b) to calculate the result. After 50 groups of numbers are substituted, 50 values can be obtained, then the maximum sum of the 50 values is___ ．
- 6. Put 1,2,3 The 100 natural numbers are randomly divided into 50 groups with two numbers in each group. Now, one of the two numbers in each group is recorded as a and the other as B
- 7. Observe the following equations: 9-1 = 8, 16-4 = 12, 25-9 = 16, 36-16 = 20 Let n be a positive integer. The following equation is () A. （n+2）2-n2=4（n+1）B. （n+1）2-（n-1）2=4nC. （n+2）2-n2=4n+1D. （n+2）2-n2=2（n+1）
- 8. 1. If 2013a ^ MB ^ 3-m and - 156ab ^ n are of the same kind, find the value of (m-n) ^ 2014 2. If the polynomial 5x ^ 2Y ^ | m | + (n-3) y ^ 2-2 is a quartic binomial about XY, find the value of m ^ 2-2mn + n ^ 2
- 9. Mathematical problems (algebra) 12 times a number is greater than 5 times that number by 49.Find that number. Column plus explanation
- 10. Ask some algebra math questions (1) It is known that a = - 2004, B = 2003, C = - 2002, a & sup2; + B & sup2; + C & sup2; + AB + BC AC (2) To find the digit of the product of 2 to the power of 1990 and 3 to the power of 1991 (3) Find X-Y when x + y = 7, X & sup2; + Y & sup2; = 25 (4) Given that a, B, C, D are nonnegative integers, and AC + BD + AD + BC = 199, find a + B + C + D (5) Given a & sup2; - 3A + 1 = 0, find the negative quadratic power of a + 1 / a A & sup2; + A, the quartic power of a + the negative quartic power of A One more question: given X-Y = 5, Y-Z = 4, find X & sup2; + Y & sup2; + Z & sup2; - xy-z & sup2; This problem may be wrong. If not, please solve it
- 11. If a natural number (except 0) is an odd number multiplied by 3 plus 1, and an even number divided by 2, what will happen? What is this phenomenon called? Why
- 12. For a natural number, do the following operation: if it is an even number, divide by 2; if it is an odd number, do the following operation for a natural number: if it is an even number, divide by 2; if it is an odd number, add 1. Do this until 1, and the operation stops. Find how many numbers become 1 after 10 operations?
- 13. If it is even, divide it by 2. If it is odd, multiply it by 3 and then add 1, What's the final result, A0, B1, C2, D3
- 14. Write a natural number (except 0), which is even, divide it by 2, which is odd, multiply it by 3, and then add 1 If you repeat this method, you can get a lot of numbers. What do you find after you get a lot of numbers
- 15. The difference between a natural number and its reciprocal is 32 / 33. What is it
- 16. The difference between the reciprocal of two natural numbers is 182 / 1. What is the sum of these two natural numbers?
- 17. The difference between the reciprocal of two adjacent natural numbers is 1182, and the sum of these two numbers is 1182______ ．
- 18. The sum of a natural number and its reciprocal is 8.125______ ．
- 19. The difference between a natural number and its reciprocal is 3 / 2
- 20. The difference between the reciprocal of two natural numbers is 1 / 12. What is the product of the two numbers