The form of - 10 is 2K pie + a (0 ≤ a < 2K pie, K is an integer) It's - 10, not - 10 degrees!
There is a wrong arc angle upstairs, so it can't be mixed up
-10≈-3.185π=-4π+0.815π
∴-10≈-4π+0.815π(k=-2)
RELATED INFORMATIONS
- 1. Let - 1480 ° be written as α + 2K π (K ∈ z), where 0 ≤ α < 2 π
- 2. Write - 1485 ° as 2K π + α (0 ≤ α ≤ 2 π, K ∈ z) Please help to write out the detailed calculation process, It's in the form of 2K π + α
- 3. Let - 1480 ° be written as 2K π + 2 (K ∈ Z, a ∈ [0,2 π])
- 4. If TaNx > Tan π / 5 and X is the third quadrant angle, then the value range of X is
- 5. The value range of X when TaNx = 0
- 6. When TaNx > 0, the value range of X is?
- 7. If Tan x is greater than Tan Π / 5 and X is in the third quadrant, the value range of X is obtained RT, just learn not very clear ==
- 8. If the set a = {α | π / 3 + 2K π
- 9. Given the set P = (a = 2K Π + 5 / 6 Π, K ∈ z), the set Q = (b = 2K Π - Π / 6, K ∈ z), then which set does the angle-7 / 6 Π belong to?
- 10. 6cos(2kπ+π/3)-2sin(2kπ+π/6)+3tan(2kπ) k€Z
- 11. The - 1485 ° is expressed as 2K π + a (K ∈ Z, a ∈ [0,2 π))
- 12. 1. Write - 1480 ° as 2K π + A, K ∈ Z, where 0 ≤ a < 2 π; 2. If β∈ [- 4 π, 0), and β is the same as the terminal edge of a in 1, find β
- 13. Given a ^ m = 9, a ^ n = 8, a ^ k = 4, find the value of a ^ m-2k + 3N
- 14. Given vector a = (3,1), vector b = (1,3), vector C = (k, 7), if (vector a-vector C) is parallel to vector B, then what is k equal to
- 15. It is known that 0 ° + K × 360 ° < a < 90 ° + K × 360 ° (k is an integer) Q: what quadrant angle is a? Try to write the range of the second, third and fourth quadrants
- 16. Given a = {a | 360K < a < 150 + 360K, K ∈ Z}, B = {B | - 90 + 360K < B < 45 + 360K, K ∈ Z} to find a ∩ B a ∪ B
- 17. Any proposition x belongs to {X / - 1 ≤ x ≤ 1}, and there is inequality x ^ 2-x-m
- 18. Given that a and B are rational numbers, and the root sign 2A + (root sign 2-1) B = 2 root sign 2a-1, try to find the solution set of inequality - ax & gt; 2B
- 19. If the two intersections of the line y = KX + B on the coordinate axis are a (2,0) and B (0, - 3), then the solution set of the inequality KX + B ≥ 0 is
- 20. As shown in the figure, if the line y = KX + B intersects the coordinate axis at a (- 3,0) and B (0,5), then the solution set of inequality - kx-b < 0 is______ .