Let - 1480 ° be written as α + 2K π (K ∈ z), where 0 ≤ α < 2 π

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• 1. Write - 1485 ° as 2K π + α (0 ≤ α ≤ 2 π, K ∈ z) Please help to write out the detailed calculation process, It's in the form of 2K π + α
• 2. Let - 1480 ° be written as 2K π + 2 (K ∈ Z, a ∈ [0,2 π])
• 3. If TaNx > Tan π / 5 and X is the third quadrant angle, then the value range of X is
• 4. The value range of X when TaNx = 0
• 5. When TaNx > 0, the value range of X is?
• 6. If Tan x is greater than Tan Π / 5 and X is in the third quadrant, the value range of X is obtained RT, just learn not very clear ==
• 7. If the set a = {α | π / 3 + 2K π
• 8. Given the set P = (a = 2K Π + 5 / 6 Π, K ∈ z), the set Q = (b = 2K Π - Π / 6, K ∈ z), then which set does the angle-7 / 6 Π belong to?
• 9. 6cos(2kπ+π/3)-2sin(2kπ+π/6)+3tan(2kπ) k€Z
• 10. Among the following groups of numbers, only the two numbers with the common factor 1 are () A. 13 and 91b. 26 and 18C. 9 and 85
• 11. The form of - 10 is 2K pie + a (0 ≤ a < 2K pie, K is an integer) It's - 10, not - 10 degrees!
• 12. The - 1485 ° is expressed as 2K π + a (K ∈ Z, a ∈ [0,2 π))
• 13. 1. Write - 1480 ° as 2K π + A, K ∈ Z, where 0 ≤ a < 2 π; 2. If β∈ [- 4 π, 0), and β is the same as the terminal edge of a in 1, find β
• 14. Given a ^ m = 9, a ^ n = 8, a ^ k = 4, find the value of a ^ m-2k + 3N
• 15. Given vector a = (3,1), vector b = (1,3), vector C = (k, 7), if (vector a-vector C) is parallel to vector B, then what is k equal to
• 16. It is known that 0 ° + K × 360 ° < a < 90 ° + K × 360 ° (k is an integer) Q: what quadrant angle is a? Try to write the range of the second, third and fourth quadrants
• 17. Given a = {a | 360K ＜ a ＜ 150 + 360K, K ∈ Z}, B = {B | - 90 + 360K ＜ B ＜ 45 + 360K, K ∈ Z} to find a ∩ B a ∪ B
• 18. Any proposition x belongs to {X / - 1 ≤ x ≤ 1}, and there is inequality x ^ 2-x-m
• 19. Given that a and B are rational numbers, and the root sign 2A + (root sign 2-1) B = 2 root sign 2a-1, try to find the solution set of inequality - ax & gt; 2B
• 20. If the two intersections of the line y = KX + B on the coordinate axis are a (2,0) and B (0, - 3), then the solution set of the inequality KX + B ≥ 0 is