When a and B start, the speed ratio of a and B is 5; 4. After meeting, a's speed decreases by 20%, and B's speed increases by 20%. Thus, when a arrives at B, B is still 10 kilometers away from A. how far is a and B from each other? How do you write it? I'm in a hurry

When a and B start, the speed ratio of a and B is 5; 4. After meeting, a's speed decreases by 20%, and B's speed increases by 20%. Thus, when a arrives at B, B is still 10 kilometers away from A. how far is a and B from each other? How do you write it? I'm in a hurry

After meeting, the speed ratio of a and B is: [5 × (1-20%)]: [4 × (1 + 20%)] = 5:6
After meeting, there is a whole distance between a and B: 4 △ 4 + 5 = 4 / 9
So when a arrives at B, B leaves a: 1 - (4 / 9) - (4 / 9) × (6 / 5) = 1 / 45
That is, 10 km accounts for 1 / 45 of the whole AB journey
The distance between the two places of AB: 10 ÷ (1 / 45) = 450 km