Given that the function f (x) = x divided by ax + B (a, B is constant and a ≠ 0) satisfies f (2) = 1, the equation f (x) = x has a unique solution, find the function f (x) And find the value of F (f (- 3))

Because the equation f (x) = x / (AX + b) (a, B are constant and a ≠ 0), when f (x) = x, the equation is transformed to: ax ^ 2 + BX = x, because the equation f (x) = x has a unique solution, then (B-1) ^ 2 = 0, the solution is: B = 1, because f (2) = 1, then 2 / (2a + 1) = 1, the solution is: a = 1 / 2, then f (x) = 2x / (x + 2) when x = - 3, then f (- 3) = - 6

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