If f (x) is an odd function on R, and the period of F (2x-1) is 4, if f (6) = - 2, then f (2008) + F (2010)=______ .
∵ the period of F (2x-1) is 4 ∵ the period of F (x) is 8, because the period of function is 8, so f (2008) = f (2000 + 8) = f (0) f (2010) = f (2002 + 8) = f (2) = f (- 6) and because f (x) is an odd function on R, f (6) = - 2, then f (0) = 0, f (- 6) = 2 ∵ f (2008) = 0, f
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