The definition field of function f (x) = x + 1 is [1,16], f (x) = f (2x) + f ^ 2 (x) + 1. Find the value field of function f (x)

F(x)=2x+1+(x+1)²+1
Now you should be able to do it

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1. The definition domain of function f (x) is (- ∞, 1) ∪ (1, + ∞), and f (x + 1) is an odd function. When x > 1, f (x) = 2x2-12x + 16, then the value range of real number m with two zeros of equation f (x) = m is () A. （-6，6）B. （-2，6）C. （-6，-2）∪（2，6）D. （-∞，-6）∪（6，+∞）
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