The domain of function f (x) is r, and f (2 + x) = f (2-x). If f (x) is an even function, and f (x) = 2x-1 when x is [0,2], find the expression of F (x) when x is [- 4,0]

When x is [0,2], f (x) = 2x-1,
So when x is [- 2,0], f (x) = f (- x) = - 2x-1
f(2+x)=f(2-x).
f(2+x+2)=f[2-(x+2)]=f(-x)=f(x)
The cycle is 4
In [- 4, - 2]
f(x)=2x+3

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