It is known that a = 110100 + 210101 + 310102 + +1110110, then the integral part of a is______ ．

A＝110100+210101+310102+… +1110110，=（1+2+3+… +11）+（10100+10101+10102+… +10110），=66+（10100+10101+10102+… +10110), because: 66 + 10110 × 11 < a < 66 + 10100 × 11, that is: 67 < a < 67110; therefore, the integral part of a is 67; so the answer is: 67

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